HEINE BOREL THEOREM PDF

Students sometimes struggle with the Heine-Borel Theorem; the authors certainly did the first time it was presented to them. This theorem can be hard to. Weierstrass Theorem and Heine-Borel Covering Theorem. Both proofs are two of the most elegant in mathematics. Accumulation Po. Accumulation Points. Heine-Borel Theorem. October 7, Theorem 1. K C Rn is compact if and only if every open covering 1Uαl of K has a finite subcovering. 1Uα1,Uα2,,Uαs l. Author: Tugore Tausho Country: Estonia Language: English (Spanish) Genre: Medical Published (Last): 8 February 2008 Pages: 88 PDF File Size: 19.57 Mb ePub File Size: 2.14 Mb ISBN: 995-8-62458-314-8 Downloads: 44919 Price: Free* [*Free Regsitration Required] Uploader: Yozshurisar I’ll disect what Hardy discusses below. Lemma closed interval is compact In classical mathematics: Even more trivially, if the real line is not endowed with the usual metric, it may fail to have the Heine-Borel property.

Then at least one of the 2 n sections of T 0 must require an infinite subcover of Cotherwise C itself would have a finite subcover, by uniting together the finite covers of the sections. Retrieved from ” https: A generalisation applies to all metric spaces and even to uniform spaces. It’s easy to prove that S S is closed precisely if it is a complete metric space as with the induced metricand similarly S S is bounded precisely if it is totally bounded.

We could also try to generalise Theorem to subspaces of other metric spaces, but this fails: This page was last edited on 22 Decemberat My instincts tells me no, but I am unsure of why. Since all the closed intervals are homeomorphic it is sufficient to show the statement for [ 01 ] [0,1]. Let S be a subset of R n. S S is closed and bounded. Email Required, but never shown.

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And that’s how you’d find Heine-Borel stated today.

Let S S be a uniform space. Central to the theory was the concept of uniform continuity and the theorem stating that every continuous function on a closed interval is uniformly continuous.

Heine–Borel theorem

Post as a guest Name. Through bisection of each of the sides of T 0the box T 0 can be broken up into 2 n sub n -boxes, each of which theirem diameter equal to half the diameter of T 0. This subcover is the finite union of balls of radius 1. In Russian constructivismalready Theorems and can be refuted using hene open-cover definition, but CTB spaces are still important. Thus, T 0 is compact. The proof above applies tbeorem almost no change to showing that any compact subset S of a Hausdorff topological space X is closed in X. Ua contradiction. borfl Continuing in like manner yields a decreasing sequence of nested n -boxes:. Note that we say a set of real numbers is closed if every convergent sequence in that set has its limit in that set.